-64=(x-5)(x+11)

Solution for -64=(x-5)(x+11) equation:

-64=(x-5)(x+11)

We move all terms to the left:

-64-((x-5)(x+11))=0

We multiply parentheses ..

-((+x^2+11x-5x-55))-64=0


We calculate terms in parentheses: -((+x^2+11x-5x-55)), so:

(+x^2+11x-5x-55)

We get rid of parentheses

x^2+11x-5x-55

We add all the numbers together, and all the variables

x^2+6x-55

Back to the equation:

-(x^2+6x-55)


We get rid of parentheses

-x^2-6x+55-64=0

We add all the numbers together, and all the variables

-1x^2-6x-9=0

a = -1; b = -6; c = -9;
Δ = b2-4ac
Δ = -62-4·(-1)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{-2}=-3$