-65-b-3b=b-11+5b

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Solution for -65-b-3b=b-11+5b equation: 



-65-b-3b=b-11+5b

We move all terms to the left:

-65-b-3b-(b-11+5b)=0

We add all the numbers together, and all the variables

-b-3b-(6b-11)-65=0

We add all the numbers together, and all the variables

-4b-(6b-11)-65=0

We get rid of parentheses

-4b-6b+11-65=0

We add all the numbers together, and all the variables

-10b-54=0

We move all terms containing b to the left, all other terms to the right

-10b=54

b=54/-10

b=-5+2/5

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