-68+23x=12x+28x

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Solution for -68+23x=12x+28x equation: 



-68+23x=12x+28x

We move all terms to the left:

-68+23x-(12x+28x)=0

We add all the numbers together, and all the variables

23x-(+40x)-68=0

We get rid of parentheses

23x-40x-68=0

We add all the numbers together, and all the variables

-17x-68=0

We move all terms containing x to the left, all other terms to the right

-17x=68

x=68/-17

x=-4

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