-68+30=10(3k-7)+2

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Solution for -68+30=10(3k-7)+2 equation: 



-68+30=10(3k-7)+2

We move all terms to the left:

-68+30-(10(3k-7)+2)=0

We add all the numbers together, and all the variables

-(10(3k-7)+2)-38=0



We calculate terms in parentheses: -(10(3k-7)+2), so:

10(3k-7)+2

We multiply parentheses

30k-70+2

We add all the numbers together, and all the variables

30k-68

Back to the equation:

-(30k-68)



We get rid of parentheses

-30k+68-38=0

We add all the numbers together, and all the variables

-30k+30=0

We move all terms containing k to the left, all other terms to the right

-30k=-30

k=-30/-30

k=1

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