-68+30x=10(3x-7)+2

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Solution for -68+30x=10(3x-7)+2 equation: 



-68+30x=10(3x-7)+2

We move all terms to the left:

-68+30x-(10(3x-7)+2)=0



We calculate terms in parentheses: -(10(3x-7)+2), so:

10(3x-7)+2

We multiply parentheses

30x-70+2

We add all the numbers together, and all the variables

30x-68

Back to the equation:

-(30x-68)



We get rid of parentheses

30x-30x+68-68=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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