-68+3k=10(3k-7)+2

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Solution for -68+3k=10(3k-7)+2 equation: 



-68+3k=10(3k-7)+2

We move all terms to the left:

-68+3k-(10(3k-7)+2)=0



We calculate terms in parentheses: -(10(3k-7)+2), so:

10(3k-7)+2

We multiply parentheses

30k-70+2

We add all the numbers together, and all the variables

30k-68

Back to the equation:

-(30k-68)



We get rid of parentheses

3k-30k+68-68=0

We add all the numbers together, and all the variables

-27k=0

k=0/-27

k=0

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