-68+7y+8=3(4y-2)-9

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Solution for -68+7y+8=3(4y-2)-9 equation: 



-68+7y+8=3(4y-2)-9

We move all terms to the left:

-68+7y+8-(3(4y-2)-9)=0

We add all the numbers together, and all the variables

7y-(3(4y-2)-9)-60=0



We calculate terms in parentheses: -(3(4y-2)-9), so:

3(4y-2)-9

We multiply parentheses

12y-6-9

We add all the numbers together, and all the variables

12y-15

Back to the equation:

-(12y-15)



We get rid of parentheses

7y-12y+15-60=0

We add all the numbers together, and all the variables

-5y-45=0

We move all terms containing y to the left, all other terms to the right

-5y=45

y=45/-5

y=-9

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