-68=6(3+6x)-7(4+x)

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Solution for -68=6(3+6x)-7(4+x) equation: 



-68=6(3+6x)-7(4+x)

We move all terms to the left:

-68-(6(3+6x)-7(4+x))=0

We add all the numbers together, and all the variables

-(6(6x+3)-7(x+4))-68=0



We calculate terms in parentheses: -(6(6x+3)-7(x+4)), so:

6(6x+3)-7(x+4)

We multiply parentheses

36x-7x+18-28

We add all the numbers together, and all the variables

29x-10

Back to the equation:

-(29x-10)



We get rid of parentheses

-29x+10-68=0

We add all the numbers together, and all the variables

-29x-58=0

We move all terms containing x to the left, all other terms to the right

-29x=58

x=58/-29

x=-2

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