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-6=(1/5)c
We move all terms to the left:
-6-((1/5)c)=0
Domain of the equation: 5)c)!=0We add all the numbers together, and all the variables
c!=0/1
c!=0
c∈R
-((+1/5)c)-6=0
We multiply all the terms by the denominator
-((+1-6*5)c)=0
We calculate terms in parentheses: -((+1-6*5)c), so:We get rid of parentheses
(+1-6*5)c
We add all the numbers together, and all the variables
(-29)c
We multiply parentheses
-29c
Back to the equation:
-(-29c)
29c=0
c=0/29
c=0
Równanie nie ma rozwiązania
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