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-6=(2/3)r
We move all terms to the left:
-6-((2/3)r)=0
Domain of the equation: 3)r)!=0We add all the numbers together, and all the variables
r!=0/1
r!=0
r∈R
-((+2/3)r)-6=0
We multiply all the terms by the denominator
-((+2-6*3)r)=0
We calculate terms in parentheses: -((+2-6*3)r), so:We get rid of parentheses
(+2-6*3)r
We add all the numbers together, and all the variables
(-16)r
We multiply parentheses
-16r
Back to the equation:
-(-16r)
16r=0
r=0/16
r=0
Równanie nie ma rozwiązania
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