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-6=-5x(x-1)-x
We move all terms to the left:
-6-(-5x(x-1)-x)=0
We calculate terms in parentheses: -(-5x(x-1)-x), so:We get rid of parentheses
-5x(x-1)-x
We add all the numbers together, and all the variables
-1x-5x(x-1)
We multiply parentheses
-5x^2-1x+5x
We add all the numbers together, and all the variables
-5x^2+4x
Back to the equation:
-(-5x^2+4x)
5x^2-4x-6=0
a = 5; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·5·(-6)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{34}}{2*5}=\frac{4-2\sqrt{34}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{34}}{2*5}=\frac{4+2\sqrt{34}}{10} $
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