-6=2(-3+i)

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Solution for -6=2(-3+i) equation: 



-6=2(-3+i)

We move all terms to the left:

-6-(2(-3+i))=0

We add all the numbers together, and all the variables

-(2(i-3))-6=0



We calculate terms in parentheses: -(2(i-3)), so:

2(i-3)

We multiply parentheses

2i-6

Back to the equation:

-(2i-6)



We get rid of parentheses

-2i+6-6=0

We add all the numbers together, and all the variables

-2i=0

i=0/-2

i=0

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