-6=2(1y+2)-7y

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Solution for -6=2(1y+2)-7y equation: 



-6=2(1y+2)-7y

We move all terms to the left:

-6-(2(1y+2)-7y)=0

We add all the numbers together, and all the variables

-(2(y+2)-7y)-6=0



We calculate terms in parentheses: -(2(y+2)-7y), so:

2(y+2)-7y

We add all the numbers together, and all the variables

-7y+2(y+2)

We multiply parentheses

-7y+2y+4

We add all the numbers together, and all the variables

-5y+4

Back to the equation:

-(-5y+4)



We get rid of parentheses

5y-4-6=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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