-6=2(y+3)-5y

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Solution for -6=2(y+3)-5y equation: 



-6=2(y+3)-5y

We move all terms to the left:

-6-(2(y+3)-5y)=0



We calculate terms in parentheses: -(2(y+3)-5y), so:

2(y+3)-5y

We add all the numbers together, and all the variables

-5y+2(y+3)

We multiply parentheses

-5y+2y+6

We add all the numbers together, and all the variables

-3y+6

Back to the equation:

-(-3y+6)



We get rid of parentheses

3y-6-6=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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