-6=2/3(2)+b

Solution for -6=2/3(2)+b equation:

-6=2/3(2)+b

We move all terms to the left:

-6-(2/3(2)+b)=0


Domain of the equation: 32+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-32

b!=-32/1

b!=-32

b∈R


We add all the numbers together, and all the variables

-(+b+2/32)-6=0

We get rid of parentheses

-b-6-2/32=0

We multiply all the terms by the denominator


-b*32-2-6*32=0

We add all the numbers together, and all the variables

-b*32-194=0

Wy multiply elements

-32b-194=0

We move all terms containing b to the left, all other terms to the right

-32b=194

b=194/-32

b=-6+1/16