-6=3/5(-5)+b

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Solution for -6=3/5(-5)+b equation: 



-6=3/5(-5)+b

We move all terms to the left:

-6-(3/5(-5)+b)=0



Domain of the equation: 5(-5)+b)!=0

b∈R



We multiply all the terms by the denominator


-(3-6*5(-5)+b)=0



We calculate terms in parentheses: -(3-6*5(-5)+b), so:

3-6*5(-5)+b

determiningTheFunctionDomain
b+3-6*5(-5)

We add all the numbers together, and all the variables

b+153

Back to the equation:

-(b+153)



We get rid of parentheses

-b-153=0

We add all the numbers together, and all the variables

-1b-153=0

We move all terms containing b to the left, all other terms to the right

-b=153

b=153/-1

b=-153

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