-6a+4(7+3a)=2(1+4a)

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Solution for -6a+4(7+3a)=2(1+4a) equation: 



-6a+4(7+3a)=2(1+4a)

We move all terms to the left:

-6a+4(7+3a)-(2(1+4a))=0

We add all the numbers together, and all the variables

-6a+4(3a+7)-(2(4a+1))=0

We multiply parentheses

-6a+12a-(2(4a+1))+28=0



We calculate terms in parentheses: -(2(4a+1)), so:

2(4a+1)

We multiply parentheses

8a+2

Back to the equation:

-(8a+2)



We add all the numbers together, and all the variables

6a-(8a+2)+28=0

We get rid of parentheses

6a-8a-2+28=0

We add all the numbers together, and all the variables

-2a+26=0

We move all terms containing a to the left, all other terms to the right

-2a=-26

a=-26/-2

a=+13

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