-6a-2(4a-5)=40

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Solution for -6a-2(4a-5)=40 equation: 



-6a-2(4a-5)=40

We move all terms to the left:

-6a-2(4a-5)-(40)=0

We multiply parentheses

-6a-8a+10-40=0

We add all the numbers together, and all the variables

-14a-30=0

We move all terms containing a to the left, all other terms to the right

-14a=30

a=30/-14

a=-2+1/7

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