-6b-10(b-8)=-80

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Solution for -6b-10(b-8)=-80 equation: 



-6b-10(b-8)=-80

We move all terms to the left:

-6b-10(b-8)-(-80)=0

We add all the numbers together, and all the variables

-6b-10(b-8)+80=0

We multiply parentheses

-6b-10b+80+80=0

We add all the numbers together, and all the variables

-16b+160=0

We move all terms containing b to the left, all other terms to the right

-16b=-160

b=-160/-16

b=+10

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