-6b-5(1-b)=-4(b-1)+3b

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Solution for -6b-5(1-b)=-4(b-1)+3b equation: 



-6b-5(1-b)=-4(b-1)+3b

We move all terms to the left:

-6b-5(1-b)-(-4(b-1)+3b)=0

We add all the numbers together, and all the variables

-6b-5(-1b+1)-(-4(b-1)+3b)=0

We multiply parentheses

-6b+5b-(-4(b-1)+3b)-5=0



We calculate terms in parentheses: -(-4(b-1)+3b), so:

-4(b-1)+3b

We add all the numbers together, and all the variables

3b-4(b-1)

We multiply parentheses

3b-4b+4

We add all the numbers together, and all the variables

-1b+4

Back to the equation:

-(-1b+4)



We add all the numbers together, and all the variables

-1b-(-1b+4)-5=0

We get rid of parentheses

-1b+1b-4-5=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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