-6c+30-4c=5(c-12)

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Solution for -6c+30-4c=5(c-12) equation: 



-6c+30-4c=5(c-12)

We move all terms to the left:

-6c+30-4c-(5(c-12))=0

We add all the numbers together, and all the variables

-10c-(5(c-12))+30=0



We calculate terms in parentheses: -(5(c-12)), so:

5(c-12)

We multiply parentheses

5c-60

Back to the equation:

-(5c-60)



We get rid of parentheses

-10c-5c+60+30=0

We add all the numbers together, and all the variables

-15c+90=0

We move all terms containing c to the left, all other terms to the right

-15c=-90

c=-90/-15

c=+6

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