-6c-5=3-(c+6)

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Solution for -6c-5=3-(c+6) equation: 



-6c-5=3-(c+6)

We move all terms to the left:

-6c-5-(3-(c+6))=0



We calculate terms in parentheses: -(3-(c+6)), so:

3-(c+6)

determiningTheFunctionDomain
-(c+6)+3

We get rid of parentheses

-c-6+3

We add all the numbers together, and all the variables

-1c-3

Back to the equation:

-(-1c-3)



We get rid of parentheses

-6c+1c+3-5=0

We add all the numbers together, and all the variables

-5c-2=0

We move all terms containing c to the left, all other terms to the right

-5c=2

c=2/-5

c=-2/5

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