-6cos(2/5x-pi/2)

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Solution for -6cos(2/5x-pi/2) equation: 


x in (-oo:+oo)

-6*cos((2/5)*x-(pi/2)) = 0

cos((2/5)*x-(pi/2)) = 0

cos((2/5)*x-(pi/2)) = 0  <=>  (2/5)*x-(pi/2) = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

(2/5)*x-t_1-(pi/2) = 0

2/5*x-t_1-(pi/2) = 0 // + -t_1-(pi/2)

2/5*x = -(-t_1-(pi/2)) // : 2/5

x = (-(-t_1-(pi/2)))/2/5

x = 5/2*(t_1+pi/2)

x = 5/2*(pi*k_1+pi/2+pi/2) i k_1 należy do I

-6*cos((2/5)*x-(pi/2)) = 0  <=>  -6 = 0 or -6*cos((2/5)*x-(pi/2)) = 0  <=>  cos((2/5)*x-(pi/2)) = 0

x = 5/2*(pi*k_1+pi/2+pi/2)

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