-6r-6(1+3r)=-6(r-5)

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Solution for -6r-6(1+3r)=-6(r-5) equation: 



-6r-6(1+3r)=-6(r-5)

We move all terms to the left:

-6r-6(1+3r)-(-6(r-5))=0

We add all the numbers together, and all the variables

-6r-6(3r+1)-(-6(r-5))=0

We multiply parentheses

-6r-18r-(-6(r-5))-6=0



We calculate terms in parentheses: -(-6(r-5)), so:

-6(r-5)

We multiply parentheses

-6r+30

Back to the equation:

-(-6r+30)



We add all the numbers together, and all the variables

-24r-(-6r+30)-6=0

We get rid of parentheses

-24r+6r-30-6=0

We add all the numbers together, and all the variables

-18r-36=0

We move all terms containing r to the left, all other terms to the right

-18r=36

r=36/-18

r=-2

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