-6u+3(u+2)=12

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Solution for -6u+3(u+2)=12 equation: 



-6u+3(u+2)=12

We move all terms to the left:

-6u+3(u+2)-(12)=0

We multiply parentheses

-6u+3u+6-12=0

We add all the numbers together, and all the variables

-3u-6=0

We move all terms containing u to the left, all other terms to the right

-3u=6

u=6/-3

u=-2

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