-6u+3(u+2)=3

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Solution for -6u+3(u+2)=3 equation:



-6u+3(u+2)=3
We move all terms to the left:
-6u+3(u+2)-(3)=0
We multiply parentheses
-6u+3u+6-3=0
We add all the numbers together, and all the variables
-3u+3=0
We move all terms containing u to the left, all other terms to the right
-3u=-3
u=-3/-3
u=1

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