-6v(v+4)=-8v-20

Solution for -6v(v+4)=-8v-20 equation:

-6v(v+4)=-8v-20

We move all terms to the left:

-6v(v+4)-(-8v-20)=0

We multiply parentheses

-6v^2-24v-(-8v-20)=0

We get rid of parentheses

-6v^2-24v+8v+20=0

We add all the numbers together, and all the variables

-6v^2-16v+20=0

a = -6; b = -16; c = +20;
Δ = b2-4ac
Δ = -162-4·(-6)·20
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{46}}{2*-6}=\frac{16-4\sqrt{46}}{-12}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{46}}{2*-6}=\frac{16+4\sqrt{46}}{-12}
$