-6v+2(4v+3)=4(v-1)-8

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Solution for -6v+2(4v+3)=4(v-1)-8 equation: 



-6v+2(4v+3)=4(v-1)-8

We move all terms to the left:

-6v+2(4v+3)-(4(v-1)-8)=0

We multiply parentheses

-6v+8v-(4(v-1)-8)+6=0



We calculate terms in parentheses: -(4(v-1)-8), so:

4(v-1)-8

We multiply parentheses

4v-4-8

We add all the numbers together, and all the variables

4v-12

Back to the equation:

-(4v-12)



We add all the numbers together, and all the variables

2v-(4v-12)+6=0

We get rid of parentheses

2v-4v+12+6=0

We add all the numbers together, and all the variables

-2v+18=0

We move all terms containing v to the left, all other terms to the right

-2v=-18

v=-18/-2

v=+9

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