-6v=-(12/7)

Solution for -6v=-(12/7) equation:

-6v=-(12/7)

We move all terms to the left:

-6v-(-(12/7))=0

We add all the numbers together, and all the variables

-6v-(-(+12/7))=0

We multiply all the terms by the denominator


-6v*7))-(-(+12=0

Wy multiply elements

-42v^2+12=0

a = -42; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-42)·12
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{14}}{2*-42}=\frac{0-12\sqrt{14}}{-84}
=-\frac{12\sqrt{14}}{-84}
=-\frac{\sqrt{14}}{-7}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{14}}{2*-42}=\frac{0+12\sqrt{14}}{-84}
=\frac{12\sqrt{14}}{-84}
=\frac{\sqrt{14}}{-7}
$