-6x(2x-4)=0

Solution for -6x(2x-4)=0 equation:

-6x(2x-4)=0

We multiply parentheses

-12x^2+24x=0

a = -12; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-12)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-12}=\frac{-48}{-24}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-12}=\frac{0}{-24}
=0
$