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-6x(x+4)=-42
We move all terms to the left:
-6x(x+4)-(-42)=0
We add all the numbers together, and all the variables
-6x(x+4)+42=0
We multiply parentheses
-6x^2-24x+42=0
a = -6; b = -24; c = +42;
Δ = b2-4ac
Δ = -242-4·(-6)·42
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12\sqrt{11}}{2*-6}=\frac{24-12\sqrt{11}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12\sqrt{11}}{2*-6}=\frac{24+12\sqrt{11}}{-12} $
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