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-6x(x-2)=-6(-x+2)
We move all terms to the left:
-6x(x-2)-(-6(-x+2))=0
We add all the numbers together, and all the variables
-6x(x-2)-(-6(-1x+2))=0
We multiply parentheses
-6x^2+12x-(-6(-1x+2))=0
We calculate terms in parentheses: -(-6(-1x+2)), so:We get rid of parentheses
-6(-1x+2)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
-6x^2+12x-6x+12=0
We add all the numbers together, and all the variables
-6x^2+6x+12=0
a = -6; b = 6; c = +12;
Δ = b2-4ac
Δ = 62-4·(-6)·12
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*-6}=\frac{-24}{-12} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*-6}=\frac{12}{-12} =-1 $
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