-6x-(3)(3x+12)=39

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Solution for -6x-(3)(3x+12)=39 equation: 



-6x-(3)(3x+12)=39

We move all terms to the left:

-6x-(3)(3x+12)-(39)=0

We multiply parentheses

-6x-9x-36-39=0

We add all the numbers together, and all the variables

-15x-75=0

We move all terms containing x to the left, all other terms to the right

-15x=75

x=75/-15

x=-5

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