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-6x-16=6-2x(x+4)
We move all terms to the left:
-6x-16-(6-2x(x+4))=0
We calculate terms in parentheses: -(6-2x(x+4)), so:We get rid of parentheses
6-2x(x+4)
determiningTheFunctionDomain -2x(x+4)+6
We multiply parentheses
-2x^2-8x+6
Back to the equation:
-(-2x^2-8x+6)
2x^2+8x-6x-6-16=0
We add all the numbers together, and all the variables
2x^2+2x-22=0
a = 2; b = 2; c = -22;
Δ = b2-4ac
Δ = 22-4·2·(-22)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6\sqrt{5}}{2*2}=\frac{-2-6\sqrt{5}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6\sqrt{5}}{2*2}=\frac{-2+6\sqrt{5}}{4} $
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