-6x-3(1+5)=-8(x-4)+4

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Solution for -6x-3(1+5)=-8(x-4)+4 equation: 



-6x-3(1+5)=-8(x-4)+4

We move all terms to the left:

-6x-3(1+5)-(-8(x-4)+4)=0

We add all the numbers together, and all the variables

-6x-(-8(x-4)+4)-36=0



We calculate terms in parentheses: -(-8(x-4)+4), so:

-8(x-4)+4

We multiply parentheses

-8x+32+4

We add all the numbers together, and all the variables

-8x+36

Back to the equation:

-(-8x+36)



We get rid of parentheses

-6x+8x-36-36=0

We add all the numbers together, and all the variables

2x-72=0

We move all terms containing x to the left, all other terms to the right

2x=72

x=72/2

x=36

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