-6x-3(5x+1)=-8(x-4)+4

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Solution for -6x-3(5x+1)=-8(x-4)+4 equation:



-6x-3(5x+1)=-8(x-4)+4
We move all terms to the left:
-6x-3(5x+1)-(-8(x-4)+4)=0
We multiply parentheses
-6x-15x-(-8(x-4)+4)-3=0
We calculate terms in parentheses: -(-8(x-4)+4), so:
-8(x-4)+4
We multiply parentheses
-8x+32+4
We add all the numbers together, and all the variables
-8x+36
Back to the equation:
-(-8x+36)
We add all the numbers together, and all the variables
-21x-(-8x+36)-3=0
We get rid of parentheses
-21x+8x-36-3=0
We add all the numbers together, and all the variables
-13x-39=0
We move all terms containing x to the left, all other terms to the right
-13x=39
x=39/-13
x=-3

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