-6x-3(x+5x)=-8(x-4)+4

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Solution for -6x-3(x+5x)=-8(x-4)+4 equation:



-6x-3(x+5x)=-8(x-4)+4
We move all terms to the left:
-6x-3(x+5x)-(-8(x-4)+4)=0
We add all the numbers together, and all the variables
-6x-3(+6x)-(-8(x-4)+4)=0
We multiply parentheses
-6x-18x-(-8(x-4)+4)=0
We calculate terms in parentheses: -(-8(x-4)+4), so:
-8(x-4)+4
We multiply parentheses
-8x+32+4
We add all the numbers together, and all the variables
-8x+36
Back to the equation:
-(-8x+36)
We add all the numbers together, and all the variables
-24x-(-8x+36)=0
We get rid of parentheses
-24x+8x-36=0
We add all the numbers together, and all the variables
-16x-36=0
We move all terms containing x to the left, all other terms to the right
-16x=36
x=36/-16
x=-2+1/4

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