-6x-4(3-4x)=3(x-3)-17

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Solution for -6x-4(3-4x)=3(x-3)-17 equation: 



-6x-4(3-4x)=3(x-3)-17

We move all terms to the left:

-6x-4(3-4x)-(3(x-3)-17)=0

We add all the numbers together, and all the variables

-6x-4(-4x+3)-(3(x-3)-17)=0

We multiply parentheses

-6x+16x-(3(x-3)-17)-12=0



We calculate terms in parentheses: -(3(x-3)-17), so:

3(x-3)-17

We multiply parentheses

3x-9-17

We add all the numbers together, and all the variables

3x-26

Back to the equation:

-(3x-26)



We add all the numbers together, and all the variables

10x-(3x-26)-12=0

We get rid of parentheses

10x-3x+26-12=0

We add all the numbers together, and all the variables

7x+14=0

We move all terms containing x to the left, all other terms to the right

7x=-14

x=-14/7

x=-2

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