-6x-4(3-8x)+14=12(-x-11.5)-4x

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Solution for -6x-4(3-8x)+14=12(-x-11.5)-4x equation: 



-6x-4(3-8x)+14=12(-x-11.5)-4x

We move all terms to the left:

-6x-4(3-8x)+14-(12(-x-11.5)-4x)=0

We add all the numbers together, and all the variables

-6x-4(-8x+3)-(12(-1x-11.5)-4x)+14=0

We multiply parentheses

-6x+32x-(12(-1x-11.5)-4x)-12+14=0



We calculate terms in parentheses: -(12(-1x-11.5)-4x), so:

12(-1x-11.5)-4x

We add all the numbers together, and all the variables

-4x+12(-1x-11.5)

We multiply parentheses

-4x-12x-138

We add all the numbers together, and all the variables

-16x-138

Back to the equation:

-(-16x-138)



We add all the numbers together, and all the variables

26x-(-16x-138)+2=0

We get rid of parentheses

26x+16x+138+2=0

We add all the numbers together, and all the variables

42x+140=0

We move all terms containing x to the left, all other terms to the right

42x=-140

x=-140/42

x=-3+1/3

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