-6x-4(3x-4)=2(x-12)

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Solution for -6x-4(3x-4)=2(x-12) equation: 



-6x-4(3x-4)=2(x-12)

We move all terms to the left:

-6x-4(3x-4)-(2(x-12))=0

We multiply parentheses

-6x-12x-(2(x-12))+16=0



We calculate terms in parentheses: -(2(x-12)), so:

2(x-12)

We multiply parentheses

2x-24

Back to the equation:

-(2x-24)



We add all the numbers together, and all the variables

-18x-(2x-24)+16=0

We get rid of parentheses

-18x-2x+24+16=0

We add all the numbers together, and all the variables

-20x+40=0

We move all terms containing x to the left, all other terms to the right

-20x=-40

x=-40/-20

x=+2

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