-6x2+21x=17

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Solution for -6x2+21x=17 equation:



-6x^2+21x=17
We move all terms to the left:
-6x^2+21x-(17)=0
a = -6; b = 21; c = -17;
Δ = b2-4ac
Δ = 212-4·(-6)·(-17)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{33}}{2*-6}=\frac{-21-\sqrt{33}}{-12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{33}}{2*-6}=\frac{-21+\sqrt{33}}{-12} $

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