-6x2+22x+40=0

Solution for -6x2+22x+40=0 equation:

-6x^2+22x+40=0

a = -6; b = 22; c = +40;
Δ = b2-4ac
Δ = 222-4·(-6)·40
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-38}{2*-6}=\frac{-60}{-12}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+38}{2*-6}=\frac{16}{-12}
=-1+1/3
$