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-6x^2+23x+4=0
a = -6; b = 23; c = +4;
Δ = b2-4ac
Δ = 232-4·(-6)·4
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-25}{2*-6}=\frac{-48}{-12} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+25}{2*-6}=\frac{2}{-12} =-1/6 $
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