-6x2+600=0

Solution for -6x2+600=0 equation:

-6x^2+600=0

a = -6; b = 0; c = +600;
Δ = b2-4ac
Δ = 02-4·(-6)·600
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-6}=\frac{-120}{-12}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-6}=\frac{120}{-12}
=-10
$