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-6y+10=-4y(2y+2)
We move all terms to the left:
-6y+10-(-4y(2y+2))=0
We calculate terms in parentheses: -(-4y(2y+2)), so:We get rid of parentheses
-4y(2y+2)
We multiply parentheses
-8y^2-8y
Back to the equation:
-(-8y^2-8y)
8y^2+8y-6y+10=0
We add all the numbers together, and all the variables
8y^2+2y+10=0
a = 8; b = 2; c = +10;
Δ = b2-4ac
Δ = 22-4·8·10
Δ = -316
Delta is less than zero, so there is no solution for the equation
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