-6y+3(y+4)=27

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Solution for -6y+3(y+4)=27 equation:



-6y+3(y+4)=27
We move all terms to the left:
-6y+3(y+4)-(27)=0
We multiply parentheses
-6y+3y+12-27=0
We add all the numbers together, and all the variables
-3y-15=0
We move all terms containing y to the left, all other terms to the right
-3y=15
y=15/-3
y=-5

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