-6y+40=2(y-4)

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Solution for -6y+40=2(y-4) equation: 



-6y+40=2(y-4)

We move all terms to the left:

-6y+40-(2(y-4))=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

-6y-2y+8+40=0

We add all the numbers together, and all the variables

-8y+48=0

We move all terms containing y to the left, all other terms to the right

-8y=-48

y=-48/-8

y=+6

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