-6y+40=2(y-4)

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Solution for -6y+40=2(y-4) equation:



-6y+40=2(y-4)
We move all terms to the left:
-6y+40-(2(y-4))=0
We calculate terms in parentheses: -(2(y-4)), so:
2(y-4)
We multiply parentheses
2y-8
Back to the equation:
-(2y-8)
We get rid of parentheses
-6y-2y+8+40=0
We add all the numbers together, and all the variables
-8y+48=0
We move all terms containing y to the left, all other terms to the right
-8y=-48
y=-48/-8
y=+6

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