-6y+8(3y-2)=9-5(-8-y)

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Solution for -6y+8(3y-2)=9-5(-8-y) equation: 



-6y+8(3y-2)=9-5(-8-y)

We move all terms to the left:

-6y+8(3y-2)-(9-5(-8-y))=0

We add all the numbers together, and all the variables

-6y+8(3y-2)-(9-5(-1y-8))=0

We multiply parentheses

-6y+24y-(9-5(-1y-8))-16=0



We calculate terms in parentheses: -(9-5(-1y-8)), so:

9-5(-1y-8)

determiningTheFunctionDomain
-5(-1y-8)+9

We multiply parentheses

5y+40+9

We add all the numbers together, and all the variables

5y+49

Back to the equation:

-(5y+49)



We add all the numbers together, and all the variables

18y-(5y+49)-16=0

We get rid of parentheses

18y-5y-49-16=0

We add all the numbers together, and all the variables

13y-65=0

We move all terms containing y to the left, all other terms to the right

13y=65

y=65/13

y=5

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