-6z+43-4z+47=2(z+21)

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Solution for -6z+43-4z+47=2(z+21) equation:



-6z+43-4z+47=2(z+21)
We move all terms to the left:
-6z+43-4z+47-(2(z+21))=0
We add all the numbers together, and all the variables
-10z-(2(z+21))+90=0
We calculate terms in parentheses: -(2(z+21)), so:
2(z+21)
We multiply parentheses
2z+42
Back to the equation:
-(2z+42)
We get rid of parentheses
-10z-2z-42+90=0
We add all the numbers together, and all the variables
-12z+48=0
We move all terms containing z to the left, all other terms to the right
-12z=-48
z=-48/-12
z=+4

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