-6z=2(-z-10)

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Solution for -6z=2(-z-10) equation: 



-6z=2(-z-10)

We move all terms to the left:

-6z-(2(-z-10))=0

We add all the numbers together, and all the variables

-6z-(2(-1z-10))=0



We calculate terms in parentheses: -(2(-1z-10)), so:

2(-1z-10)

We multiply parentheses

-2z-20

Back to the equation:

-(-2z-20)



We get rid of parentheses

-6z+2z+20=0

We add all the numbers together, and all the variables

-4z+20=0

We move all terms containing z to the left, all other terms to the right

-4z=-20

z=-20/-4

z=+5

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